ExamSpark Class 12 Mathematics
Subject: CBSE Class 12 Mathematics (NCERT Full-Syllabus Practice)
Detailed Question Analysis
Q1. For a relation \(R\) on a set \(A = \{1, 2, 3\}\) defined as \(R = \{(1,1), (2,2), (3,3), (1,2), (2,3)\}\), which of the following is true?
Correct Answer: Option C (\(R\) is reflexive but neither symmetric nor transitive.)
Concept Explanation: Relation reflexive hai kyunki \((1,1), (2,2), (3,3) \in R\). \((1,2) \in R\) par \((2,1) \notin R\) (not symmetric). \((1,2)\) aur \((2,3) \in R\) par \((1,3) \notin R\) (not transitive).
Q2. The principal value of \(\cos^{-1}(\cos(7\pi/6))\) is:
Correct Answer: Option B (\(5\pi/6\))
Concept Explanation: Principal value branch of \(\cos^{-1}x\) is \([0, \pi]\). \(7\pi/6\) iske bahar hai. We write \(\cos(2\pi - 5\pi/6) = \cos(5\pi/6)\). So, \(5\pi/6\) is the answer.
Q3. If \(A\) is a square matrix such that \(A^2 = I\), then \(A^{-1}\) is equal to:
Correct Answer: Option B (\(A\))
Concept Explanation: Given \(A^2 = I\). Multiply both sides by \(A^{-1}\): \(A^{-1}A^2 = A^{-1}I \implies (A^{-1}A)A = A^{-1} \implies IA = A^{-1} \implies A = A^{-1}\).
Q4. The value of \(k\) for which \(f(x) = \frac{\tan 3x}{x}\) for \(x \neq 0\) and \(f(0) = k\) is continuous at \(x=0\) is:
Correct Answer: Option A (\(3\))
Concept Explanation: Continuity ke liye \(\lim_{x \to 0} \frac{\tan 3x}{x} = f(0)\). \(\lim_{x \to 0} 3 \cdot \frac{\tan 3x}{3x} = 3(1) = 3\).
Q5. The slope of the tangent to the curve \(y = x^3 - x + 1\) at the point where \(x = 2\) is:
Correct Answer: Option B (\(11\))
Concept Explanation: Slope is \(dy/dx\). \(dy/dx = 3x^2 - 1\). At \(x=2\), \(3(2^2) - 1 = 12 - 1 = 11\).
Q6. \(\int e^x (\tan x + \log(\sec x)) \, dx\) equals:
Correct Answer: Option B (\(e^x \log(\sec x) + C\))
Concept Explanation: Form \(\int e^x (f(x) + f'(x)) dx = e^x f(x) + C\). Let \(f(x) = \log(\sec x)\), then \(f'(x) = \frac{1}{\sec x} \cdot \sec x \tan x = \tan x\). Result matches option B.
Q7. The degree of the differential equation \(\frac{d^2y}{dx^2} + \sqrt{1 + \left(\frac{dy}{dx}\right)^3} = 0\) is:
Correct Answer: Option B (\(2\))
Concept Explanation: Pehle radical hatayenge: \(\frac{d^2y}{dx^2} = -\sqrt{1 + (dy/dx)^3}\). Square both sides: \((d^2y/dx^2)^2 = 1 + (dy/dx)^3\). Highest order is 2, and its power is 2.
Q8. A unit vector perpendicular to both vectors \(\vec{a} = 2\hat{i} + \hat{j} + \hat{k}\) and \(\vec{b} = \hat{i} - \hat{j} + 2\hat{k}\) is:
Correct Answer: Option A (\(\frac{3\hat{i} - 3\hat{j} - 3\hat{k}}{\sqrt{27}}\))
Concept Explanation: \(\vec{n} = \vec{a} \times \vec{b} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ 2 & 1 & 1 \\ 1 & -1 & 2 \end{vmatrix} = \hat{i}(2+1) - \hat{j}(4-1) + \hat{k}(-2-1) = 3\hat{i} - 3\hat{j} - 3\hat{k}\). Unit vector = \(\frac{\vec{n}}{|\vec{n}|}\).
Q9. If a line makes angles \(\alpha, \beta, \gamma\) with axes, then \(\sin^2\alpha + \sin^2\beta + \sin^2\gamma\) is:
Correct Answer: Option B (\(2\))
Concept Explanation: \(\cos^2\alpha + \cos^2\beta + \cos^2\gamma = 1\). Convert to sine: \((1-\sin^2\alpha) + (1-\sin^2\beta) + (1-\sin^2\gamma) = 1 \implies 3 - (\sin^2\alpha + \sin^2\beta + \sin^2\gamma) = 1 \implies \text{sum} = 2\).
Q10. The probability of getting a total of 7 when two dice are thrown is:
Correct Answer: Option A (\(1/6\))
Concept Explanation: Pairs for 7: \((1,6), (2,5), (3,4), (4,3), (5,2), (6,1)\). Total 6 outcomes out of 36. \(6/36 = 1/6\).
Q11. A wire of length 20m is to be cut into two pieces. One piece is made into a square and the other into a circle. To minimize the combined area, the side of the square is:
Correct Answer: Option A (\(20/(\pi+4)\))
Concept Explanation: Let square side \(s\) and circle radius \(r\). \(4s + 2\pi r = 20 \implies r = (20-4s)/2\pi\). Area \(A = s^2 + \pi r^2\). Differentiate \(dA/ds = 0\) to get \(s\).
Q12. The maximum value of \(Z = 3x + 4y\) subject to \(x+y \le 4, x \ge 0, y \ge 0\) is:
Correct Answer: Option B (\(16\))
Concept Explanation: Corner points: \((0,0), (4,0), (0,4)\). \(Z(0,0)=0, Z(4,0)=12, Z(0,4)=16\). Max is 16.
Q13. If \(P(A) = 0.4, P(B) = 0.8, P(B|A) = 0.6\), then \(P(A|B)\) is:
Correct Answer: Option A (\(0.3\))
Concept Explanation: \(P(A \cap B) = P(B|A) \cdot P(A) = 0.6 \times 0.4 = 0.24\). \(P(A|B) = P(A \cap B) / P(B) = 0.24 / 0.8 = 0.3\).
Q14. Assertion (A): The function \(f(x) = |x|\) is not differentiable at \(x=0\). Reason (R): A function is differentiable if its graph is a smooth curve.
Correct Answer: Option B (Both A and R are true but R is not correct explanation.)
Concept Explanation: A is true (sharp corner at \(x=0\)). R is also a general truth, but differentiability is defined by LHD=RHD, not just "smoothness."
Q15. Assertion (A): \(|adj A| = |A|^{n-1}\) for a square matrix of order \(n\). Reason (R): For any matrix \(A\), \(A \cdot adj A = |A|I\).
Correct Answer: Option A (Both A and R are true and R is correct explanation of A.)
Concept Explanation: \(A \cdot adj A = |A|I\). Determinant lenge: \(|A \cdot adj A| = | |A|I | \implies |A| \cdot |adj A| = |A|^n \cdot |I| = |A|^n\). Thus \(|adj A| = |A|^{n-1}\).
Q16. [Case Study] A box contains 5 red and 5 black balls. Two balls are drawn one by one without replacement. What is the probability that both balls are red?
Correct Answer: Option C (\(2/9\))
Concept Explanation: \(P(R_1) = 5/10 = 1/2\). \(P(R_2|R_1) = 4/9\). \(P(R_1 \cap R_2) = 1/2 \times 4/9 = 2/9\).
Q17. [Case Study] Continuing from Q16, what is the probability that the second ball is red given the first was black?
Correct Answer: Option B (\(5/9\))
Concept Explanation: First ball black: 9 balls left, 5 red, 4 black. \(P(R_2|B_1) = 5/9\).
Q18. The number of all possible matrices of order \(3 \times 3\) with each entry 0 or 1 is:
Correct Answer: Option D (\(512\))
Concept Explanation: 9 positions, each has 2 choices. \(2^9 = 512\).
Q19. The area of the region bounded by \(y^2 = 4ax\) and \(x = a\) is:
Correct Answer: Option A (\(8/3 a^2\))
Concept Explanation: Area \(= 2 \int_0^a \sqrt{4ax} \, dx = 4\sqrt{a} \int_0^a x^{1/2} \, dx = 4\sqrt{a} [x^{3/2} / (3/2)]_0^a = 8/3 \sqrt{a} \cdot a^{3/2} = 8/3 a^2\).
Q20. If \(\int_0^a f(x) \, dx = \int_0^a f(a-x) \, dx\), find \(\int_0^{\pi/2} \frac{\sin x}{\sin x + \cos x} \, dx\).
Correct Answer: Option B (\(\pi/4\))
Concept Explanation: Standard property. \(I = \int_0^{\pi/2} \frac{\cos x}{\cos x + \sin x} \, dx\). \(2I = \int_0^{\pi/2} 1 \, dx = \pi/2 \implies I = \pi/4\).