Ch 2: Polynomials (Division Algorithm)
This page covers the remaining exercises from the traditional NCERT textbook: Division Algorithm for Polynomials (Old Ex 2.3).
Old Exercise 2.3 Solutions
💡 Concept: Division Algorithm states that p(x) = g(x) × q(x) + r(x)
Q1. Divide the polynomial p(x) by the polynomial g(x) and find the quotient and remainder in each of the following:
(i) p(x) = x³ - 3x² + 5x - 3, g(x) = x² - 2
Solution:
We divide x³ - 3x² + 5x - 3 by x² - 2
Quotient, q(x) = x - 3
Remainder, r(x) = 7x - 9
Q3. Obtain all other zeroes of 3x⁴ + 6x³ - 2x² - 10x - 5, if two of its zeroes are √(5/3) and -√(5/3).
Most Important / 4 MarksSolution:
Since √(5/3) and -√(5/3) are zeroes, then:
(x - √(5/3))(x + √(5/3)) is a factor of the given polynomial.
Using (a-b)(a+b) = a² - b²:
(x² - 5/3) = 0
Multiplying by 3, we get 3x² - 5 as a factor.
Now, we divide the given polynomial by (3x² - 5):
The quotient is x² + 2x + 1.
To find the remaining zeroes, we factorize the quotient:
x² + 2x + 1 = 0
(x + 1)² = 0
x = -1, -1
Therefore, all the zeroes are √(5/3), -√(5/3), -1, and -1.
Advanced PYQs (Long Division)
Q. On dividing x³ - 3x² + x + 2 by a polynomial g(x), the quotient and remainder were x - 2 and -2x + 4, respectively. Find g(x).
Solution:
Given:
Dividend, p(x) = x³ - 3x² + x + 2
Quotient, q(x) = x - 2
Remainder, r(x) = -2x + 4
By Division Algorithm:
p(x) = g(x) × q(x) + r(x)
Substituting the values:
x³ - 3x² + x + 2 = g(x) × (x - 2) + (-2x + 4)
x³ - 3x² + x + 2 + 2x - 4 = g(x) × (x - 2)
x³ - 3x² + 3x - 2 = g(x) × (x - 2)
Therefore, g(x) = (x³ - 3x² + 3x - 2) / (x - 2)
On dividing the numerator by (x - 2) using long division, we get the quotient:
x² - x + 1
Hence, g(x) = x² - x + 1.